1) A 0.50 kg object is at rest. A 3.00 N force to the right acts on the object during a time interval of 1.50 s
a) What is the impulse?
b) What is the velocity of the object at the end of this time interval?
2) A 2250 kg car traveling to the west at 20.0 m/s slows down uniformly and comes to a stop.
a) What is the impulse delivered to the car?
b) How long it would take the car to come to a stop if the force on the car is 8450 N to the east?
3) A 2.5 kg ball strikes a wall with a velocity of 7.5 m/s to the right. The ball is in contact with a wall for 0.25 s.
a)What is the change in momentum?
b) What is the impulse delivered?
c) What is the constant force exerted on the ball by the wall?
4) A 0.15 kg baseball moving at +26 m/s is slowed to a stop by a catcher who exerts a constant force of -390 N.
a) What is the change in momentum?
b) What is the impulse delivered?
c) how long does it take this force to stop?
.need help!! :)
>>formula's<<
P=w/t
P=energy/time
P=mad/t
P= Fd/t
Thank You!! :) <3 i really need help :)
Sure, I can help you step-by-step with these questions. Let's start with the first one:
1) A 0.50 kg object is at rest. A 3.00 N force to the right acts on the object during a time interval of 1.50 s.
a) To find the impulse, you can use the formula: Impulse = Force x Time. Substituting the given values, Impulse = 3.00 N x 1.50 s = 4.5 N.s.
b) To find the velocity of the object at the end of this time interval, you can use the formula: Impulse = Change in Momentum. Rearranging the formula, Change in Momentum = Mass x Change in Velocity. Since the object is initially at rest, the initial velocity is 0. Therefore, Change in Momentum = Mass x Final Velocity.
We can find the final velocity using the formula: Final Velocity = Initial Velocity + (Impulse / Mass). Since the initial velocity is 0, Final Velocity = 0 + (4.5 N.s / 0.50 kg) = 9 m/s.
Therefore, the velocity of the object at the end of 1.50 s is 9 m/s.
Now let's move to the second question:
2) A 2250 kg car traveling to the west at 20.0 m/s slows down uniformly and comes to a stop.
a) To find the impulse delivered to the car, you can use the formula: Impulse = Change in Momentum. Since the car comes to a stop, the final momentum is 0. Therefore, Impulse = Final Momentum - Initial Momentum.
The initial momentum of the car can be calculated using the formula: Initial Momentum = Mass x Initial Velocity. Initial Momentum = 2250 kg x (-20 m/s) = -45000 kg.m/s.
Therefore, Impulse = 0 - (-45000 kg.m/s) = 45000 kg.m/s.
b) To find how long it would take the car to come to a stop if the force on the car is 8450 N to the east, you can use the formula: Impulse = Force x Time. Rearranging the formula, Time = Impulse / Force.
Time = 45000 kg.m/s / 8450 N ≈ 5.32 s.
Therefore, it would take approximately 5.32 seconds for the car to come to a stop.
Now, let's move to the third question:
3) A 2.5 kg ball strikes a wall with a velocity of 7.5 m/s to the right. The ball is in contact with a wall for 0.25 s.
a) The change in momentum can be calculated using the formula: Change in Momentum = Mass x Change in Velocity.
Since the ball bounces back from the wall, the final velocity is in the opposite direction. Therefore, Change in Velocity = Final Velocity - Initial Velocity = (-7.5 m/s) - (7.5 m/s) = -15 m/s.
Therefore, the change in momentum = 2.5 kg x (-15 m/s) = -37.5 kg.m/s.
b) The impulse delivered can be calculated using the formula: Impulse = Change in Momentum. Therefore, the impulse delivered is -37.5 kg.m/s.
c) The constant force exerted on the ball by the wall can be calculated using the formula: Impulse = Force x Time. Rearranging the formula, Force = Impulse / Time.
The given time is 0.25 s. Therefore, the force exerted by the wall on the ball is -37.5 kg.m/s / 0.25 s = -150 N.
Therefore, the constant force exerted on the ball by the wall is -150 N.
Now let's move to the last question:
4) A 0.15 kg baseball moving at +26 m/s is slowed to a stop by a catcher who exerts a constant force of -390 N.
a) The change in momentum can be calculated using the formula: Change in Momentum = Mass x Change in Velocity.
Since the baseball is slowed down to a stop, the change in velocity is the final velocity (which is 0) minus the initial velocity. Therefore, Change in Momentum = Mass x Change in Velocity = 0.15 kg x (0 m/s - 26 m/s) = -3.9 kg.m/s.
Therefore, the change in momentum is -3.9 kg.m/s.
b) The impulse delivered can be calculated using the formula: Impulse = Change in Momentum. Therefore, the impulse delivered is -3.9 kg.m/s.
c) To find how long it takes for the force to stop the baseball, you can use the formula: Impulse = Force x Time. Rearranging the formula, Time = Impulse / Force.
Time = -3.9 kg.m/s / -390 N = 0.01 s.
Therefore, the force takes 0.01 seconds to stop the baseball.
I hope that helps! Let me know if you have any further questions.
I'll be happy to help you with these physics problems! Let's go through each question step by step.
1) Impulse is defined as the change in momentum. In this case, the object is initially at rest, so the initial momentum is zero. The force acting on the object is 3.00 N to the right, and the time interval is 1.50 seconds.
a) To find impulse, we can use the formula:
Impulse = Force × Time
Impulse = 3.00 N × 1.50 s
Impulse = 4.50 N·s
b) To find the velocity of the object at the end of the time interval, we can use the formula:
Impulse = Change in momentum
Change in momentum = Mass × Change in velocity
Since the object was initially at rest, the change in velocity is equal to the final velocity. We can rearrange the formula to find the final velocity:
Change in momentum = Mass × (Final velocity - Initial velocity)
0.50 kg × (Final velocity - 0) = 4.50 N·s
Final velocity = 4.50 N·s / 0.50 kg
Final velocity = 9.00 m/s
2) In this scenario, the car is slowing down uniformly until it comes to a stop. We need to find the impulse delivered to the car and the time it takes for the car to stop.
a) The impulse delivered to the car is equal to the change in momentum of the car. Since the car comes to a stop, the final momentum is zero. Therefore, the impulse is equal to the initial momentum:
Impulse = Initial momentum
The initial momentum can be calculated using the formula:
Momentum = Mass × Velocity
Initial momentum = 2250 kg × (-20.0 m/s) (since the car is moving to the west)
Initial momentum = -45,000 kg·m/s
So, the impulse delivered to the car is -45,000 kg·m/s.
b) To find the time it takes for the car to stop, we can use the formula:
Impulse = Force × Time
Rearrange the formula to solve for time:
Time = Impulse / Force
Time = (-45,000 kg·m/s) / 8450 N
Time ≈ -5.32 s
The negative sign indicates that the force is acting in the opposite direction of the car's initial velocity, causing it to slow down and eventually stop.
3) In this question, we have a ball striking a wall. We need to find the change in momentum, impulse delivered, and the constant force exerted by the wall.
a) The change in momentum can be calculated using the formula:
Change in momentum = Mass × (Final velocity - Initial velocity)
Change in momentum = 2.5 kg × (0 - 7.5 m/s) (since the ball strikes the wall and comes to rest)
Change in momentum = -18.75 kg·m/s
b) The impulse delivered is equal to the change in momentum, so it is also -18.75 kg·m/s.
c) To find the constant force exerted by the wall, we can use the formula:
Impulse = Force × Time
Since we are given the time interval of contact (0.25 s), we can rearrange the formula to solve for force:
Force = Impulse / Time
Force = (-18.75 kg·m/s) / 0.25 s
Force = -75 N (the negative sign indicates the force exerted by the wall is in the opposite direction)
4) For the last question, we have a baseball being slowed down to a stop by a catcher. We need to find the change in momentum, impulse delivered, and the time it takes for the force to stop the baseball.
a) The change in momentum can be found using the same formula as before:
Change in momentum = Mass × (Final velocity - Initial velocity)
Change in momentum = 0.15 kg × (0 - 26 m/s) (since the baseball comes to rest)
Change in momentum = -3.9 kg·m/s
b) The impulse delivered is equal to the change in momentum, so it is also -3.9 kg·m/s.
c) To find the time it takes for the force to stop the baseball, we can use the formula:
Impulse = Force × Time
Again, rearrange the formula to solve for time:
Time = Impulse / Force
Time = (-3.9 kg·m/s) / (-390 N)
Time = 0.01 s
So, it takes 0.01 s for the catcher's force to stop the baseball.
Remember to always double-check your calculations and units to ensure accuracy. I hope this explanation helps you with your physics problems! Let me know if you have any further questions.