A school dance has 228 students. There are 63 fewer girls than twice as many boys.

How many boys and girls attended the dance?

For this problem let us assume that 'B' represents # of boys and 'G' represents # of girls

In the question we have been told that 'twice the # of boys' = 'twice the # of boys - 63' girls.

Total # of students = B + G
228= B + (2B-63)
228 = B + 2B - 63
228 = B - 63
228+63 = 3B
291 = 3B
291/3 = B
97 = B

So we now know that we have 97 boys.
In order to find out how many girls we have we simply subtract the # of boys from the total # of students:

G = 228-97
G = 131

Therefore, we have 131 girls and 97 boys.

Let me just correct the 2nd line I posted:

"In the question we have been told that 'twice the # of boys' = 'twice the # of boys - 63' girls. "

That is wrong. I meant to say:

"The # of girls = twice the # of boys-63"

To find out how many boys and girls attended the dance, we can set up equations based on the given information.

Let's assume the number of boys at the dance is represented by 'x', and the number of girls is represented by 'y'.

According to the given information, we can form two equations:

Equation 1: Total number of students
x + y = 228

Equation 2: Girls are 63 fewer than twice as many boys
y = 2x - 63

Now, we can solve these equations simultaneously to find the values of x and y.

Substituting Equation 2 into Equation 1:

x + (2x - 63) = 228
3x - 63 = 228
3x = 228 + 63
3x = 291
x = 291/3
x = 97

Now, substitute the value of x back into Equation 1 to find the value of y:

97 + y = 228
y = 228 - 97
y = 131

Therefore, there were 97 boys and 131 girls who attended the school dance.