One reaction that produces hydrogen gas can

be represented by the unbalanced chemical
equation
Mg(s) + HCl(aq) −! MgCl2(aq) + H2(g) .
What mass of HCl is consumed by the reac-
tion of 2.96 mol of magnesium?
Answer in units of g

Mg + 2HCl ==> MgCl2 + H2

2.96 mols Mg x (2 mol HCl/1 mol Mg) = 2.96 x 2/1 = ? mols.
Then mols HCl x molar mass HCl = grams HCl.

To determine the mass of HCl consumed in the reaction, we need to use the molar ratio between magnesium (Mg) and hydrochloric acid (HCl) in the balanced chemical equation.

First, we need to balance the given equation:

Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)

From the balanced equation, we see that 1 mol of Mg reacts with 2 mol of HCl.

Given that 2.96 mol of Mg is consumed in the reaction, we can use the molar ratio to calculate the number of moles of HCl:

2.96 mol Mg × (2 mol HCl / 1 mol Mg) = 5.92 mol HCl

Now, to find the mass of HCl, we need to multiply the number of moles of HCl by its molar mass. The molar mass of hydrochloric acid (HCl) is approximately 36.461 g/mol.

5.92 mol HCl × 36.461 g/mol = 216.207 g

Therefore, the mass of HCl consumed by the reaction of 2.96 mol of magnesium is 216.207 g.