Algebra

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I am confused on how solve this substitution problem
4y+3=3y+x
2x+4y=18
If you can, show work please (:

  • Algebra -

    I am pretty sure this goes like this
    4y+3=3y+x (i)
    2x+4y=18 (ii)

    Rearrange (i) so that x=4y+3-3y
    Take (ii) and sub x
    it will become 2(4y+3-3y)+4y= 18
    2(y+3)+4y =18
    2y+6+4y=18
    6y+6=18
    6y=18-6
    6y=12
    y=12/6
    y=2 (iii)
    Now use what you found for y in (iii) and sub in the (ii or i to get x)
    lets take (i) 4y+3=3y+x
    from (iii) 4(2)+3=3(2)+x
    11=6+x
    x= 11-6
    x=5
    let me know if that's clear enough

  • Algebra -

    Yes that is thank you so much (:

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