Algebra 1
posted by NEED HELP NOW!! .
Find three consecutive even numbers such that the difference between 3 times the first number and twice the second number is 1/3 the third number.
also, my teacher told me to use an equation.

Even numbers have a differnce of two.
2, 6, and 8 are consecutive even numbers.
Let n = 1st
Let n + 2 = 2nd
Let n + 4 = 3rd
3(n)  2(2n+2) = 1/3(n+4)
Here is the equation. Can you solve it? 
let n be first number
n+2 be second number
n+4 be third number.
3n2(n+2)=1/3 * (n+4)
solve for n, then the other numbers. 
No JJ, 2,6,8 are not consecutive even numbers. Your equation is wrong.

That isn't the answer. That was just an example of what consecutive even numbers mean to show why we are using n, n+2 and n+4. My equation is the same as yours.

3(n)  2(2n+2) = 1/3(n+4)
is not the same as
3n2(n+2)=1/3 * (n+4)
again, 2,6, 8 are not consecutive even numbers.
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