If you have one $50 bill, one $20 bill, one $10 bill and one $100 bill, how many possible sums of money consisting of three bills each, can be formed?
50, 20, 10 = 80
50, 20, 100 = 170
50, 10, 100 = 160
20, 10, 100 = 130
so 4 sums, correct me if i am wrong
To find the number of possible sums of money consisting of three bills, we need to consider all possible combinations of bills. Since the order of bills does not matter (i.e., we are only interested in the total sum), we can use combinations.
We have four bills: $50, $20, $10, and $100. We need to choose three bills from these four.
The number of combinations of selecting three bills from four can be calculated using the formula for combinations:
nCr = n! / [(n-r)! * r!]
n represents the total number of items (in this case, the four bills), and r represents the number of items we want to choose (in this case, three bills).
Using this formula, we can calculate the number of possible combinations of three bills:
4C3 = 4! / [(4-3)! * 3!]
= 4! / [1! * 3!]
= 4! / 3!
= (4 * 3 * 2 * 1) / (3 * 2 * 1)
= 4
Therefore, there are four possible sums of money consisting of three bills that can be formed.