Math
posted by Tperry .
A college student decides that school work limits him to a total of no more than 36
hours per week at his two parttime jobs. He earns $6 per hour hanging wall paper and
he has a sales job that pays $8 per hour. He needs to earn at least $245 per week to
cover his expenses. Write a system of inequalities that shows the various numbers of
hours he can work at each job. Let h represent the number of hours spent hanging wall
paper and let s represent the number of hours spent working at the sales job.

hours: h + s < or equal to 36
6h + 8s > or equal to 245
You can solve these just like you would equations.
How would you solve h + s = 36
6h + 8s = 245
Multiply the first equation by 6 and then combine the equations to eliminate the x and solve for y. Substitute back in to solve for x.
then go back to the original inequalities to find the various numbers houwer worked 
well you would isolate y and i got s< or equal to h+36

I meant to say s and h.
You could do that which issubstitution or you could use the addition/elimination method
6h 6s <= 216
6h +8s >= 245
2s =461
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