A point charge Q1=−2 μC is located at x=0, and a point charge Q2=+8 μC is placed at x=−0.5 m on the x-axis of a cartesian coordinate system.The goal of this problem is to determine the electric field, E⃗ (x)=E(x)xˆ, at various points along the x-axis

(a)What is E(x) (in N/C) for x=-82.0 m ?
What is E(x) (in N/C) at x=-0.17 m?
What is E(x) (in N/C) at x=34 m?

(b) At what point (apart from |x|=∞), is E(x)=0? Express your answer in meters.

The First is -7.901.

Just this in the moment.

c) 46.244

b) 1283994.39504

and the 2) (B) is 0.5

SHOW YOUR WORK PLEASE. DO NOT JUST PUT THE ANSWER, BUT PUT THE WORK TO GET THE ANSWER. THANK YOU!

(a)What is E(x) (in N/C) for x=-48.5 m ?

What is E(x) (in N/C) at x=-0.1 m?
What is E(x) (in N/C) at x=96 m?
(b) At what point (apart from |x|=∞), is E(x)=0? Express your answer in meters.

To determine the electric field (E) at various points along the x-axis in a cartesian coordinate system, we can use the principle of superposition. The electric field due to multiple point charges is given by the sum of the electric fields produced individually by each charge.

Given:
Q1 = -2 μC at x = 0
Q2 = +8 μC at x = -0.5 m

(a) To calculate the electric field at various points on the x-axis, we can use Coulomb's law:

Electric field due to a point charge Q = k * (Q / r^2)

where k is the electrostatic constant, Q is the charge, and r is the distance from the charge.

For x = -82.0 m:
Here, there is only one charge (Q1 = -2 μC) contributing to the electric field. The distance (r) from the charge to the point is 82.0 m. Plugging the values into Coulomb's law:

E(x) = k * (Q1 / r^2)

Substituting the given values:
E(x) = (9 * 10^9 Nm^2/C^2) * (-2 * 10^-6 C) / (82.0 m)^2

Simplifying the equation will yield the value of E(x) in N/C.

Similarly, for x = -0.17 m and x = 34 m, we need to calculate the electric field due to both Q1 and Q2.

(b) To determine the point where E(x) = 0, we need to find the location where the electric field due to both charges cancels each other out. This happens when the electric fields due to Q1 and Q2 are equal in magnitude but opposite in direction.

To find this point, we need to set up an equation equating the electric field due to Q1 and Q2 and solve for x.

E(Q1) = E(Q2)
k * (Q1 / r1^2) = k * (Q2 / r2^2)

Substituting the given values for Q1, Q2, r1, and r2, we can solve the equation to find the value of x where E(x) = 0. This point will give us the distance from the origin at which the net electric field is zero.