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cmsd

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Your question: "The shorter diagonal of a rhombus is 50 mm long. Each of its obtuse angles measures 140. Find the length of each side."

  • cmsd -

    Then each of the acute angles is 40, and the the angle bisected by the shorter diagonol divides into two 70deg

    law of sines:
    50mm/Sin40= s/Sne70

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