if 5.06 g of limestone decomposes by heat to 4.25 g of calcium oxide and carbon dioxide gas,what is the mass of carbon dioxide gas produced?

.....CaCO3 ==> CaO + CO2

.....5.06g.....4.25 + ?
The Conservation of mass says nothing is lost, so 4.25 + ? = 5.06.

I thought about answering this one, but the question reads 4.25g of CaO and CO2; wasn't sure if 4.25g was referring only to CaO or both CO2. I completely agree with DrBob222.

To find the mass of carbon dioxide gas produced in the decomposition of limestone, you need to determine the difference in mass between the initial limestone and the final products (calcium oxide and carbon dioxide).

Step 1: Calculate the mass of carbon dioxide gas:
Mass of limestone (initial mass) = 5.06 g
Mass of calcium oxide (final mass) = 4.25 g

Step 2: Determine the mass difference:
Mass of carbon dioxide = Mass of limestone - Mass of calcium oxide

Mass of carbon dioxide = 5.06 g - 4.25 g

Mass of carbon dioxide = 0.81 g

Therefore, the mass of carbon dioxide gas produced in the decomposition of limestone is 0.81 grams.