If a ball is thrown straight up at a speed of 24.7 m/s, for how long of a time will it continue to rise before it starts to fall back down?
To determine the time it takes for the ball to continue rising before it starts to fall back down, we can use the equations of motion.
When the ball reaches its maximum height, its final velocity will be zero. At that point, the only force acting on it will be gravity pulling it back down. The initial velocity when the ball is thrown upward is 24.7 m/s.
We can use the equation:
v = u + at
where:
v = final velocity (0 m/s because the ball reaches its maximum height and starts to fall back down)
u = initial velocity (24.7 m/s)
a = acceleration (-9.8 m/s^2, as it is the acceleration due to gravity)
t = time
Rearranging the equation to solve for time (t):
0 = 24.7 - 9.8t
9.8t = 24.7
t = 24.7 / 9.8
t ≈ 2.52 seconds
Therefore, the ball will continue to rise for approximately 2.52 seconds before it starts to fall back down.