A rectangular yard is twice as long as wide the perimeter is 120ft. What are the yards dimensions? W : L :
I got. W : 10. And ll: 50
Is that right ?
No, look at your answer... Your length is 4 times as long as your width... How did you come up with your answer?
To solve this problem, we need to use the formula for the perimeter of a rectangle, which is given by P = 2(L + W), where L is the length and W is the width.
We are given that the perimeter is 120ft, so we can set up the equation as follows:
120 = 2(L + W)
We also know that the length is twice as long as the width, so we can write L = 2W.
Substituting L = 2W into the equation, we have:
120 = 2(2W + W)
120 = 2(3W)
120 = 6W
W = 20
Now that we have found the width, we can substitute this value back into the equation L = 2W to get the length:
L = 2(20)
L = 40
Therefore, the dimensions of the rectangular yard are:
Width (W) = 20ft
Length (L) = 40ft
So, your answer W: 20 and L: 40 is correct, not W: 10 and L: 50.