physics
posted by matt .
a curling rock with a mass 22 kg is traveling 0 degrees at 3m/s and collides with a stationary object with the same mass the collision is a glancing one and the struck roce is moving 1m/s at 65 degrees what is the velocity after the collision

The final momentum is 22*3 kg m/s
you are given one objects mass, velocity after collision.
for that object, zero deg momentum is 22*1*cos65
subtract that from the initial momentum at zero, and you have the zero deg momentum of rock 2.
Now the other direction>
at 90 deg, the moving rock momentum is 22*1*sin65
the other rock must be moving then at momentum 22^1*sin(180+65)
now, you can find the velocity and direction of the original rock after collision, you have two components at ninety degrees.
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