phy
posted by faaash .
A spy satellite is in circular orbit around Earth. It makes one revolution in 6.01 hours.
how high above earth?
acceleration?

change time to seconds for the period.
v=2PI h/period
v^2=(2PI)^2/period^2
v^2/r= 9.8*(re^2/r^2) where r is the orbital radius.
solve for r, then altitude is rre.