If I have 50 mL of Lead(II) Nitrate, it is possible for me to calculate how many mole is 1 mL of the substance? Thanks
Yes, it is possible to calculate the number of moles of Lead(II) Nitrate in 1 mL of the substance if you have the total volume and concentration of the solution. Here's how you can calculate it:
1. Start by calculating the number of moles of Lead(II) Nitrate in the entire 50 mL solution. To do this, you need to know the molarity (concentration) of the solution. The molarity is typically represented using a unit called "mol/L" or "M."
2. Multiply the volume of the solution (50 mL) by its molarity to obtain the number of moles of Lead(II) Nitrate in the solution. The unit for the volume must be in liters, so you need to convert 50 mL into liters by dividing it by 1000 since 1 L = 1000 mL.
Moles = Volume (L) x Molarity (mol/L)
3. Now, since you know the number of moles in the entire solution, you can calculate how many moles are present in just 1 mL. Divide the number of moles by the total volume of the solution.
Moles in 1 mL = Moles / Total volume (L)
You now have the number of moles of Lead(II) Nitrate in 1 mL of the substance.