Find the margin of error for c,s, and n.
C= 0.90, s=2.3, n=36?
Please help asap....
I am unfamiliar with your designations. What do C, s and n stand for?
No worries PsyDAG. I have finally figured it out on the TI-83 Plus. It only took me forever. lol But thank you.
For anyone who needs this answer in the future is 0.631
To find the margin of error for c, s, and n, we need more information about the given values.
1. Confident Level (c): The margin of error depends on the level of confidence desired for the sample estimation. The commonly used confidence levels are 90%, 95%, and 99%. Please provide the desired confidence level as a percentage.
2. Standard Deviation (s): The margin of error also depends on the variability or dispersion of the sample data. The standard deviation (s) measures this spread. Please provide the standard deviation value for the given sample.
3. Sample Size (n): The margin of error will be influenced by the size of the sample. Knowing the sample size (n) is crucial in calculating the margin of error. Please provide the sample size.
Once you provide the missing information, I can guide you on how to calculate the margin of error for c, s, and n.