College Algebra
posted by Efrain .
This is my question 2x^28x=25
I cant seem to figure out how to solve for x?

Add the 25 to the other side...
2x^28x+25=0,
Now use the quadratic formula to solve for x...
Hope this helps 
I was told to start with
x^28x+16=7/2 so where do i go from there? 
2x^2  8x =25
divide each term by 2
using completing the square,
x^2  4x = 25/2
take 1/2 the coefficient of the x term, square it, then add it to each side
x^2  4x +4 = 25/2 +4
(x2)^2 = 17/2 or 34/4 , (I anticipated to take √ of both sides)
x 2 = ± √34/2 = ± i√34/2
x = 4/2 ± i√34/2 = (4 ± i√34)/2
or ... by the formula
2x^2  8x + 25 = 0
x = (8 ± √136)/4
= (8 ± 2√34)/2
= (4 ± i√34)/2 
I was told to start with
x^28x+16=7/2 so where do i go from there? That's after / by 2.
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