What is the relative atomic mass of naturally occuring copper to four decimal places when you are given 69,09% of copper-63 with a relative atomic mass of 62,9298 with 30,91% of copper-65, with a relative atomic mass of 64,9278?

I need your help guyz plz!

0.6906(mass) + 0.3091(mass) = avg mass.

Help guys

To calculate the relative atomic mass of naturally occurring copper, you can use the weighted average of the isotopes along with their respective abundance percentages. Here's how you can calculate it:

Step 1: Convert the abundance percentages to decimals.
- Copper-63 abundance: 69.09% = 0.6909
- Copper-65 abundance: 30.91% = 0.3091

Step 2: Multiply the atomic mass of each isotope by its respective abundance.
- Copper-63: 62.9298 * 0.6909 = 43.40320782
- Copper-65: 64.9278 * 0.3091 = 20.05235998

Step 3: Add the results obtained in Step 2.
- 43.40320782 + 20.05235998 = 63.4555678

Step 4: Round the final result to four decimal places.
- Rounded to four decimal places, the relative atomic mass of naturally occurring copper is 63.4556.

Therefore, the relative atomic mass of naturally occurring copper to four decimal places is 63.4556.