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if A=(3,5) and B=(4,1).find the equation of locus of point p which are equidistant from points A and B

  • maths -

    such a point must lie on the right-bisector of AB
    midpoint of AB =(7/2 , 3)
    slope of AB = (1-5)/(4-3) = -4
    so slope of perpendicular = 1/4

    equation:
    y-3 = (1/4)(x-7/2)
    y - 3 = (1/4)x - 7/8
    y = (1/4)x +3 - 7/8
    y = (1/4)x + 17/8

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