physics
posted by renu .
a stone dropped from the top of a cliff received ground in 4 second and burries itself at 0.8 meter into mud.calculate height and retardation.

How does a stone "receive" ground? Do you mean "reach" ground?
How do you define "retardation"? The backwards drag fiorce in mud?
The height H that the stone falls in time t is
H = (g/2)*t^2
H = 4.9*16 = 78.4 meters
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