If a horizontal force of 200Newton is just sufficient to along the wooden,floor,calculate the coefficient of static friction
I'm sorry but, your trunk is missing.
What is the weight or mass of whatever you are moving?
200 N/(Weight) = coefficient of static friction
To calculate the coefficient of static friction, you need to know the normal force and the applied force. In this case, the normal force is the force exerted by the wooden floor on the object.
However, the given information does not provide the normal force, so we need to make some assumptions to proceed with the calculation. Normally, the normal force is equal to the weight of the object resting on the surface. The weight of the object can be calculated by multiplying its mass (given in kilograms) by the acceleration due to gravity (approximately 9.8 m/s²). Let's assume the mass is 10 kilograms.
Weight (W) = mass × acceleration due to gravity
W = 10 kg × 9.8 m/s²
W = 98 N
Since the wooden floor is horizontal, the normal force is equal to the weight of the object. Therefore, the normal force is also 98 Newtons in this case.
Now, you can proceed to calculate the coefficient of static friction using the equation:
Coefficient of static friction (μs) = applied force / normal force
Given: Applied force (F) = 200 Newtons, Normal force (N) = 98 Newtons
Coefficient of static friction (μs) = 200 N / 98 N
Coefficient of static friction (μs) ≈ 2.04
Therefore, the coefficient of static friction between the object and the wooden floor is approximately 2.04.