I need to calcuted the molarity from this
12.5 g of ethylene glycol antifreeze dissolved in o.100kg of water. Density of solution is 1.0 g/mL
I know molarity if mole of solute / L of solution.
I am confused on how to find the L of solution. Do I add 12.5 and .100g to get the solution mass. Since 12.5 is solute and .100 g is solvent.
#4 in Related Questions, below should provide the formulas you need
To calculate the molarity, you need to find the number of moles of the solute (ethylene glycol) and the volume of the solution. Let's break it down step by step:
1. Find the moles of ethylene glycol:
Moles = Mass / Molar mass
The molar mass of ethylene glycol (C2H6O2) is 46.07 g/mol. Therefore:
Moles of ethylene glycol = 12.5 g / 46.07 g/mol
2. Find the volume of the solution:
To determine the volume of the solution, you need to know the density of the solution. You mentioned that the density is 1.0 g/mL. Since the solute (ethylene glycol) is being dissolved in water, you can assume that the total volume of the solution is equal to the mass of the solution divided by the density.
Mass of the solution = Mass of ethylene glycol + Mass of water
Mass of the solution = 12.5 g + 0.100 kg = 12.5 g + 100 g (since 1 kg = 1000 g)
Mass of the solution = 112.5 g
Volume of the solution = Mass of the solution / Density
Volume of the solution = 112.5 g / 1.0 g/mL = 112.5 mL (since 1 mL = 1 cm^3)
3. Convert the volume to liters:
Molarity is typically expressed in moles per liter (mol/L). Therefore, convert the volume from milliliters to liters:
Volume of the solution = 112.5 mL / 1000 mL/L
Volume of the solution = 0.1125 L
4. Calculate the molarity:
Molarity = Moles of solute / Volume of solution
Molarity = Moles of ethylene glycol / Volume of the solution
Now that you have the moles of ethylene glycol (step 1) and the volume of the solution in liters (step 3), you can calculate the molarity of the solution.