Serena paid $20.20 for 36 folders. She bought 16 more folders than rulers. If each folder cost $0.50 more than each ruler, how much did each folder cost?
I think there is an error is the statement of the problem.
Serena paid $20.20 for 36 folders. Right there you could find out the price of the folders. Should it say $20.20 for 36 folders and ??? rulers??
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0.70
To solve this problem, we can set up a system of equations to represent the information given.
Let's denote the cost of each ruler as "r" and the cost of each folder as "f". From the first piece of information, we know that Serena paid a total of $20.20 for 36 folders. So, we can create the equation:
36f = $20.20
Next, we are told that Serena bought 16 more folders than rulers. So, if we let the number of rulers be "x", then the number of folders would be "x + 16". Given that each folder costs $0.50 more than each ruler, we can create another equation:
f = r + $0.50
Now, let's substitute the value of "f" from the second equation into the first equation to solve for "r" and find the cost of each ruler:
36(r + $0.50) = $20.20
Expanding the equation:
36r + 18 = $20.20
Subtracting 18 from both sides:
36r = $2.20
Now, dividing both sides by 36:
r ≈ $0.0611
Therefore, each ruler cost approximately $0.0611.
To find the cost of each folder, we can substitute the value of "r" back into the second equation:
f = $0.0611 + $0.50
Simplifying the equation:
f ≈ $0.5611
Therefore, each folder cost approximately $0.5611.