balance each of the following chemical equations ,using the change in oxidation number method. cu +h2so4=cuso4+so2+h2o

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balance by oxidation number method.cu+h2so4=cuso4+so2+h2o

To balance the chemical equation Cu + H2SO4 = CuSO4 + SO2 + H2O using the change in oxidation number method, follow these steps:

Step 1: Determine the oxidation states of each element in the equation.
Cu: Copper is a transition metal, so its oxidation state can vary. Let's assume it is +2 in CuSO4.
H: Hydrogen generally has an oxidation state of +1.
S: Sulfur in H2SO4 has an oxidation state of +6.
O: Oxygen has an oxidation state of -2.
To balance the equation, we want to ensure that the total change in oxidation numbers is equal on both sides of the equation.

Step 2: Focus on the elements that change their oxidation numbers.
In this equation, Cu goes from 0 to +2, and S goes from +6 to +4.

Step 3: Balance the elements with changing oxidation numbers.
Start by balancing Cu. Since it goes from 0 to +2, we need two Cu atoms on the left side to give 2x +1 charge increase.

2Cu + H2SO4 = CuSO4 + SO2 + H2O

Step 4: Balance other elements.
Now let's balance the Sulfur, which will involve balancing both Sulfate (SO4) and Sulfur Dioxide (SO2).
Sulfur is reduced from +6 in H2SO4 to +4 in SO2, so it decreases by 2 units. To balance this, we multiply the entire CuSO4 term by 2.

2Cu + H2SO4 = 2CuSO4 + SO2 + H2O

Step 5: Finally, balance hydrogen and oxygen.
Count the number of hydrogen and oxygen atoms on both sides of the equation. On the left side, there are 2 hydrogen atoms from H2SO4 and 2 hydrogen atoms from H2O, for a total of 4 hydrogen atoms. On the right side, there is only 1 hydrogen atom from H2O. We can balance this by multiplying H2O on the right side by 4.

2Cu + H2SO4 = 2CuSO4 + SO2 + 4H2O

The balanced equation using the change in oxidation number method is:

2Cu + H2SO4 = 2CuSO4 + SO2 + 4H2O