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Logarithms
Solve log4 x + log4(x2)=log4(15) I know how do the example in my book but I don't know what I'm doing wrong here. log4 x + log4(x2)=log4(15) log4 [x + log4(x2)]=log4(15) (x^2 + x)=4 x^2 + x4=0 
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solve for x: log4 X  log4 2 = 2 log(2x) = 2 Now what do I do? 
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solve for x: log4 X  log4 2 = 2 log(2x) = 2 Now what do I do? 
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Logarithm!!! Select all of the following that are true statements: (a) log(2x) = log(2) + log(x) (b) log(3x) = 3 log(x) (c) log(12y) = 2 log(2) + log(3y) (d) log(5y) = log(20y) – log(4) (e) log(x) = log(5x) – log(5) (f) ln(25) … 
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How do you solve the equation log(x+6)log(2x+1)=log4 
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1. Log10²x+log10x²=log10² 21 2. Log4(log2x)+log2(log4x)=2 3. X^logx+5/3= 10^5+log x 4. Log 1/2(x1)+ log 1/2(x+1)log1/√2(7x)=1 
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I don't understand how to do these w/o calc. I tried to write it in a way that will make someone understand how to read it. Hope I typed it clear enough.Thanks so much for the help anyone! How to find the exact value of logarithm: … 
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Using logarithms to rewrite the expression: 1.) log4.(4)^3x= 2.) 6 log6 36= 3.) 3 log 2 1/2= 4.) 1/4 log4 16 
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Solve the equations. Log(6x1) = Log(x+1) + log4