Sjava

posted by .

Log x=log25+log4

  • Sjava -

    log(x) = log(25*4)
    x = 25*4 = 100

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Logarithms

    Solve log4 x + log4(x-2)=log4(15) I know how do the example in my book but I don't know what I'm doing wrong here. log4 x + log4(x-2)=log4(15) log4 [x + log4(x-2)]=log4(15) (x^2 + x)=4 x^2 + x-4=0
  2. Algebra 2

    Simplify: 1. 2log10^5+log10^4 2. 2log3^6-log3^4 3. log4^40-log4^5 4. log4^3-log4^48 I need to see all of the steps. Thanks
  3. Math(Please check)

    solve for x: log4 X - log4 2 = 2 log(2x) = 2 Now what do I do?
  4. Math

    solve for x: log4 X - log4 2 = 2 log(2x) = 2 Now what do I do?
  5. math

    Logarithm!!! Select all of the following that are true statements: (a) log(2x) = log(2) + log(x) (b) log(3x) = 3 log(x) (c) log(12y) = 2 log(2) + log(3y) (d) log(5y) = log(20y) – log(4) (e) log(x) = log(5x) – log(5) (f) ln(25) …
  6. Calculus

    How do you solve the equation log(x+6)-log(2x+1)=log4
  7. maths

    1. Log10²x+log10x²=log10² 2-1 2. Log4(log2x)+log2(log4x)=2 3. X^logx+5/3= 10^5+log x 4. Log 1/2(x-1)+ log 1/2(x+1)-log1/√2(7-x)=1
  8. precalc

    I don't understand how to do these w/o calc. I tried to write it in a way that will make someone understand how to read it. Hope I typed it clear enough.Thanks so much for the help anyone! How to find the exact value of logarithm: …
  9. Precalc

    Using logarithms to rewrite the expression: 1.) log4.(4)^3x= 2.) 6 log6 36= 3.) 3 log 2 1/2= 4.) 1/4 log4 16
  10. math: pre-calculus

    Solve the equations. Log(6x-1) = Log(x+1) + log4

More Similar Questions