Algebra
posted by Ann .
How do I solve this equation? Please explain and do step by step.
6m squared 5m14=0

6m^2  5m  14 = 0
it's mainly trial and error. Since 5 is a relatively small number, don't expect to see factors like (6m+1)(m14)
I'd try (3m?)(2m+?)
(3m)(2m+) Hmm. nope
(6m7)(m+2) = 6m^2 + 5m  14
close, but we need 5m. So,
(6m+7)(m2) 
Then you have to set each factor equal to zero and solve for m.
I actually have another way to factor instead of trial and erro.
you multiply the 6 times 14 to get 84
Then you think of a two numbers that multiply to =84 and add up to be 5
They are 12 plus 7
rewrite as 6m^2 12m + 7m 14
group (6m^2 12m) + (7m 14)
take out common factors
6m(m 2) + 7 (m2)
factor out the m2
and you have (6m+7)(m2)
It is a newer methos and eliminates the guessing. It works every time. 
how do I solve (16)^3 +48(16)^2