# Trig

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A Ferris wheel is 40 meters in diameter and boarded from a platform that is 4 meters above the ground. The six o'clock position on the Ferris wheel is level with the loading platform. The wheel completes 1 full revolution in 2 minutes. How many minutes of the ride are spent higher than 30 meters above the ground?

• Trig -

let's use a sine function ....
amplitude = 20
period = 2π/k = 2
2k = 2π
k = π

so far we have
height = 20 sin π(t + c) + d , assuming we have a phase shift and a vertical shift
clearly, the whole sine curve has to shifted upwards by 24 units, so that the normal min of -20 becomes a min of 4
so we have
height = 20 sin π(t+c) + 24

1. when t = 0 , we want height to be 4
2. when t = 1 , we want the height to be 44

1.
4 = 20sin π(c) + 24
-20 = 20sin πc
sin πc = -1
but we know that sin 3π/2 = -1
then cπ = 3π/2
c = 3/2

equation is
height = 20 sin π(t + 3/2) + 24

check for t = 1, (should get 44)
height = 20 sin π(1 + 3/2) + 24
= 20 sin 5π/2 + 24 = 20(1) + 24 = 44

all looks good.

so we want h ≥ 30
20 sin π(t+3/2) + 24 = 30
sin π(t+3/2) = 6/20 = 3/10 = .3
setting my calculator to radians , I get
π(t+3/2) = .3047 or π-.3047 = 2.837
t + 1.5 = .3047/π or t+1.5 = 2.837/π
t = -1.403 or t = -.597

BUT, we should have positive times,
since the period of the curve is 2, adding 2 to each of these times will also satisfy the equation
so t = -1.403+2 = .597
and t = -.597 + 2 = 1.403

so for the time from t = .597 to t = 1.403 the height will be ≥ 30

So it will be above 30 for( 1.403-.597) minutes
= .806 minutes or appr 48.4 seconds

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