Calculus

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Find the area of the region bound by f(y) = 9y - y^2 and the y-axis over the interval 3 <= y <= 6.

  • Calculus -

    what's the trouble? pretty straightforward integration

    ∫[3,6] 9y - y^2 dy
    = 9/2 y^2 - 1/3 y^3 [3,6]
    = 117/2

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