# Calculus

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Find the area of the region bound by f(y) = 9y - y^2 and the y-axis over the interval 3 <= y <= 6.

• Calculus -

what's the trouble? pretty straightforward integration

∫[3,6] 9y - y^2 dy
= 9/2 y^2 - 1/3 y^3 [3,6]
= 117/2

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