Find the area of the region bound by f(y) = 9y - y^2 and the y-axis over the interval 3 <= y <= 6.
what's the trouble? pretty straightforward integration
∫[3,6] 9y - y^2 dy
= 9/2 y^2 - 1/3 y^3 [3,6]
= 117/2
∫[3,6] 9y - y^2 dy
= 9/2 y^2 - 1/3 y^3 [3,6]
= 117/2