John walks 20km due east then turns 270 degrees anticlockwise and walks another 20km. What would be his bearing from the starting point?

I think it would be best to draw a diagram for this sort of question. So John walks 20 km East.

START ----------------> JOHN (@ 20km EAST)

- So John is facing this direction -->
- If you were to turn 270 degree facing --> then you would be facing downwards or South
- So, John walks another 20 km South

If you draw this out, you'll see that you have a triangle with both the base and height being 20 km and the hypotenuse is the unknown.

From there you would use Pythagorean theorem (a^2 + b^2 = c^2) and solve for 'c' or the hypotenuse. That should be John's distance from the start.

To find the bearing from the starting point, we need to determine the direction in which John is facing after completing his journey. Let's break down the steps to find the answer:

Step 1: John walks 20km due east.
Since John walks due east, he is moving in the direction of 90 degrees (with north being 0 degrees).

Step 2: John turns 270 degrees anticlockwise.
A full circle is 360 degrees, and since John turns 270 degrees anticlockwise, he is effectively turning 90 degrees clockwise. This means his new direction is 360 degrees - 90 degrees = 270 degrees.

Step 3: John walks another 20km.
After turning, John walks 20km in the new direction, which is at a bearing of 270 degrees.

Step 4: Calculate the final bearing.
To find the final bearing, we need to add the initial bearing (east, 90 degrees) to the change in bearing due to the turn (270 degrees). The calculation is as follows: 90 degrees + 270 degrees = 360 degrees.

However, since we typically measure bearings between 0 and 360 degrees, we need to simplify the final bearing. In this case, 360 degrees is equivalent to 0 degrees. Therefore, the bearing from the starting point is 0 degrees.

So, John's bearing from the starting point is north (0 degrees).