Find the coordinates of two points on the line with the given equation. Then use the points for find the slope of the line.

1) y= -17
2) 7x-3y= -147

Thank you so much for your help.

To find the coordinates of two points on the line with the given equation, you can choose any two values for x and substitute them into the equation to find the corresponding y values.

1) For the equation y = -17, let's choose two values for x. Let's say x = 0 and x = 1.

When x = 0, substitute it into the equation: y = -17, so the corresponding point is (0, -17).

When x = 1, substitute it into the equation: y = -17, so the corresponding point is (1, -17).

Therefore, the coordinates of the two points on the line y = -17 are (0, -17) and (1, -17).

To find the slope of the line, you can use the formula: slope = (change in y) / (change in x).

Since the y-coordinate remains constant throughout the equation y = -17, the change in y is 0.

Similarly, since the equation does not contain any x terms, the change in x is also 0.

Therefore, the slope of the line y = -17 is undefined.

2) For the equation 7x - 3y = -147, we will solve for y to get it into slope-intercept form (y = mx + b).

First, let's isolate the term with y on one side of the equation:

7x - 3y = -147
-3y = -7x - 147

Next, divide both sides of the equation by -3 to isolate y:

y = (7/3)x + 49

Now that the equation is in slope-intercept form, we can see that the coefficient of x (7/3) represents the slope of the line.

Therefore, the slope of the line 7x - 3y = -147 is 7/3.

I hope this helps!