Find the coordinates of two points on the line with the given equation. Then use the points for find the slope of the line.
1) y= -17
2) 7x-3y= -147
Thank you so much for your help.
To find the coordinates of two points on the line with the given equation, you can choose any two values for x and substitute them into the equation to find the corresponding y values.
1) For the equation y = -17, let's choose two values for x. Let's say x = 0 and x = 1.
When x = 0, substitute it into the equation: y = -17, so the corresponding point is (0, -17).
When x = 1, substitute it into the equation: y = -17, so the corresponding point is (1, -17).
Therefore, the coordinates of the two points on the line y = -17 are (0, -17) and (1, -17).
To find the slope of the line, you can use the formula: slope = (change in y) / (change in x).
Since the y-coordinate remains constant throughout the equation y = -17, the change in y is 0.
Similarly, since the equation does not contain any x terms, the change in x is also 0.
Therefore, the slope of the line y = -17 is undefined.
2) For the equation 7x - 3y = -147, we will solve for y to get it into slope-intercept form (y = mx + b).
First, let's isolate the term with y on one side of the equation:
7x - 3y = -147
-3y = -7x - 147
Next, divide both sides of the equation by -3 to isolate y:
y = (7/3)x + 49
Now that the equation is in slope-intercept form, we can see that the coefficient of x (7/3) represents the slope of the line.
Therefore, the slope of the line 7x - 3y = -147 is 7/3.
I hope this helps!