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PHYSICS

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A rifle is aimed horizontally at a target 31 m away. The bullet hits the target 1.3 cm below the aiming point. Neglect air resistance.
(a) What is the bullet's time of flight?


s

(b) What is its muzzle velocity?


m/s (in the bullet's initial horizontal direction)

  • PHYSICS -

    a. d = 0.5g*t^2 = 0.013 m.
    4.9t^2 = 0.013t^2
    t^2 = 0.00265
    Tf = 0.052 s. = Fall time or time in flight.

    b. Xo * T = 31 m.
    0.052Xo = 31
    Xo = 602 m/s.

  • PHYSICS -

    x=x0+v0xt+(1/2)axt^2
    => -0.013~0+0+(1/2)(-9.8)t^2
    => 0.013~(1/2)(9.8)t^2
    => 0.013~4.9t^2
    => t~0.052s
    y=y0+v0yt+(1/2)ayt^2
    => 31~0+v0yt+(1/2)(0)(0.052)^2
    => 31~v0yt
    =>v0y~31/t
    =>v0y~31/.052
    =>v0y~6.0*10^2m/s

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