Quantum Physics
posted by qwerty .
We have a qubit in the state ψ>= √3/2 0>+ 1/2 1>, which we want to measure in the {Cos θ 0> + Sin θ 1>, Sin θ 0>  Cos θ 1>} basis. In order for the two possible outcomes to be equiprobable, what should be the value of θ in degrees? (Answer between 0 and 90.)
Respond to this Question
Similar Questions

Math  Calculus
The identity below is significant because it relates 3 different kinds of products: a cross product and a dot product of 2 vectors on the left side, and the product of 2 real numbers on the right side. Prove the identity below.  a … 
Trigonometry
Which of the following is equivalent to 1 − cos 2 θ/cos 2 θ? 
PreCalculus
If θ represents an angle such that sin2θ = tanθ  cos2θ, then sin θ  cosθ = A. √2 B. 0 C. 1 D. 2√2 What equation can I use to solve this problem? 
Physics
We have a qubit in the state ψ>= √3/2 0>+ 1/2 1>, which we want to measure in the {Cos θ 0> + Sin θ 1>, Sin θ 0>  Cos θ 1>} basis. In order for the two possible outcomes to … 
Physics
We have a qubit in the state ϕ⟩=3√20⟩+121⟩, which we want to measure in the {cosθ0⟩+sinθ1⟩,sinθ0⟩−cosθ1⟩} basis. In order for the two possible … 
trig
An object Is propelled upward at an angle θ, 45° < θ<90°, to the horizontal with an initial velocity of (Vo) feet per second from the base of a plane that makes an angle of 45° with the horizontal. If air resistance … 
Trigonometry
There are four complex fourth roots to the number 4−4√3i. These can be expressed in polar form as z1=r1(cosθ1+isinθ1) z2=r2(cosθ2+isinθ2) z3=r3(cosθ3+isinθ3) z4=r4(cosθ4+isinθ4), … 
Math Question
Given tan θ = 8/5 and sin θ < 0, find sin θ, cos θ, csc θ, sec θ, and cot θ. 
Calculusantiderivative
Find f. f ''(θ) = sin θ + cos θ, f(0) = 5, f '(0) = 3 My steps: f'(θ)=cosθsinθ+C When f'(0)=3, C=2, so f'(θ)=cosθsinθ2. f(θ)=sinθcosθ2x+D When f(0)=5, D=6, so f is … 
PRECALC
solve the equation 1. cos(θ) − sin(θ) = 1 2.2 cos(θ) tan(θ) + tan(θ) = 1 + 2 cos(θ) 3. sin(θ) cos(3θ) + cos(θ) sin(3θ) = 0 4. sin(2θ) cos(θ) − cos(2θ) sin(θ) …