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A water system of 2 in.(inside diameter) pipe, having a length of 1/4 mile, is to be flushed with a volume of water equal to twice that contained in the system. how much water (gallons) must be flushed through the system? (note: one cubic foot=7.481gal.)

  • math -

    if the pipe is full, it contains

    pi * 2^2 * 1/4 * 5280 * 12 = 199051 in^3 = 115.19 ft^3

    So, we want twice that, or

    230.38 * 7.481 = 723.5 gal

  • Math - correction -

    rats. divide that by 4, since I was using radius=2, not diameter

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