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Find the values of the six trigonometric functions for ∠A in standard position determined by the point (63, 280). Enter your answers as fractions.

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    The point is in the 1st quadrant, so all our ratios will be positive
    r^2 = 63^ + 280^2 = 82369
    r =√82369 = 287

    sinA = y/r = 280/287 = 40/41 , then cscA = 41/40
    cosA = x/r = 63/287 = 9/41 , then secA = 41/9
    tanA = y/x = 280/63 = 40/9 , then cotA = 9/40

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