Statistics
posted by Maile .
The body temperatures of adults are normally distributed with a mean of 98.6 degree F and a standard deviation of 0.60 degree F. If 36 adults are randomly selected, find the probability that their mean body temperature is greater than 98.4 degree F.

Use zscores:
z = (98.4  98.6)/(0.60/√36) = ?
Once you calculate the zscore, check a ztable for your probability. (Remember that the problem is asking to find the probability "greater than" 98.4) 
2 z=0.0228 10.0228 answer 0.9772

.01765
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