Post a New Question


posted by .

. In Flask A, you reacted 5.10 g Mg with 0.447 mol HCl. In Flask B, you reacted 24.21 g Mg with 0.998 mol HCl. Which ballon will inflate the most?

  • Chemistry -

    You have four problems to work here.
    Mg + 2HCl ==> MgCl2 + H2
    mols Mg = grams/molar mass
    Convert mols Mg to mol H2.
    mols HCl you have. Convert to mols H2.
    The SMALLER number of mols will be the correct answer for mols H2 produced.

    Do the same for flask B. The flask that produces the more mols H2 will be the one that inflates the balloon more.

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question