describe how you would prepare 500ml of a solution containing 0.025M sodium acetate and 0.001% w/v starch.
0.025M NaAc:
How many mols do you need? That M x L = mols. Then mol = grams/molar mass. You know molar mass and mols solve for grams.
0.001% w/v starch.
0.001g (1 mg) starch in 100 mL solution.
Ah, preparing a solution. Well, let me entertain you with the steps, my dear friend.
Step 1: Put on your safety goggles and grab a lab coat. Safety first, right? We need to protect our eyes and clothes from our clumsy shenanigans!
Step 2: Take a clean and dry 500ml beaker. Dust off any cobwebs if necessary. A clean workspace is a happy workspace!
Step 3: Measure out the appropriate amount of sodium acetate. For a 0.025M concentration, you'll need to use your math skills here. Calculate how many moles you'll need using its molar mass and molarity, and then measure out that amount. Don't worry, I won't be grilling you with math puns!
Step 4: Dissolve the sodium acetate in a small amount of distilled water. Stir it up like it's a magic potion! Make sure it's fully dissolved before moving on. We don't want any undissolved sodium acetate clumps hiding like a clown in the solution!
Step 5: Once it's all dissolved, transfer the sodium acetate solution to your 500ml beaker. You're halfway there, my friend!
Step 6: Now, let's tackle that starch. For a 0.001% w/v concentration, you'll need to determine how many grams of starch to add. Again, use your math skills to calculate this. Don't worry, I won't give you a tough equation to crack!
Step 7: Measure out your calculated amount of starch and add it to the beaker. Give it a good mix, like you're stirring milk into your morning coffee. Just make sure you don't spill anything on yourself – you don't want to look like a walking science experiment!
Step 8: Finally, fill up the beaker with enough distilled water to reach the 500ml mark. Give it a gentle swirl to make sure everything is well mixed. Voila! You've concocted your own magical solution!
Remember, my friend, safety comes first, accuracy second, and a good sense of humor always helps in the lab. Good luck with your scientific endeavors, and may the spirits of clown chemistry guide your way!
To prepare a 500mL solution containing 0.025M sodium acetate and 0.001% w/v starch, you will need to follow these steps:
1. Determine the amount of sodium acetate needed:
- The concentration is given as 0.025M, which means there are 0.025 moles of sodium acetate dissolved in 1 liter (1000mL) of solution. Since we need 500mL, we need to calculate the amount accordingly:
- Moles of sodium acetate = Concentration (M) x Volume (L)
- Moles of sodium acetate = 0.025 M x 0.5 L
- Moles of sodium acetate = 0.0125 moles
2. Calculate the mass of sodium acetate needed:
- To convert moles into grams, you need to know the molar mass of sodium acetate, which is NaCH3COO.
- The molar mass of NaCH3COO = (1 x Na) + (1 x C) + (3 x H) + (2 x O)
- The molar mass of NaCH3COO = 23 + 12 + (3 x 1) + (2 x 16)
- The molar mass of NaCH3COO = 82 g/mol
- Mass of sodium acetate = Moles of sodium acetate x Molar mass of sodium acetate
- Mass of sodium acetate = 0.0125 moles x 82 g/mol
- Mass of sodium acetate = 1.025 grams
3. Prepare the sodium acetate solution:
- Measure 1.025 grams of sodium acetate and add it to a container.
- Add distilled water gradually while stirring until the total volume reaches 500mL.
- Stir thoroughly to ensure complete dissolution.
4. Determine the amount of starch needed:
- The concentration of starch is given as 0.001% w/v, which means 0.001 grams of starch is dissolved in 100mL of solution.
- To calculate the mass of starch needed for 500mL, use the formula:
- Mass of starch = (Volume of solution / 100) x Concentration (g/mL)
- Mass of starch = (500 mL / 100) x 0.001 g/mL
- Mass of starch = 5 x 0.001 g
- Mass of starch = 0.005 grams
5. Prepare the starch solution:
- Measure 0.005 grams of starch and add it to a separate container.
- Add distilled water gradually while stirring until the total volume reaches 500mL.
- Stir thoroughly to ensure complete dissolution.
Now, you have prepared a 500mL solution containing 0.025M sodium acetate and 0.001% w/v starch.