Chemistry

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At 900.0K, the equilibrium comstant (kp) for the following reaction is 0.345

2SO2 (g) + O2 (g) yields 2SO3 (g)

At equilibrium the partial pressure of SO2 is 35.0 atm and that of O2 is 15.9 atm. What is the partial pressure of SO3 in atm?

6.20 X 10-4 ( I think it is this one)
192
82.0
40.0

  • Chemistry -

    I don't think so.
    Why do you think that is the one?
    Kp = 0.345 = (p^2)SO3/(p)O2*(p^2)SO2
    0.345 = (p^2)SO3 = 15.9*(35.0)^2

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