Math

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A farmer uses 1034 meters of fencing to enclose a rectangular region and also to subdivide the region into three smaller rectangular regions by placing a fence parallel to one of the sides. Find the demensions that produce the greatest enclosed area.

  • Math -

    After making your sketch and creating the 3 rectangles
    let the length of each rectangle be x, let the width of each rectangle be y
    So the area of the whole enclosed area = 3xy

    also : 4x + 6y = 1034
    6y = 1034 - 4x
    y = (1034 - 4x)/6

    area = 3xy - 3x(1034-4x)/6
    = 517x - 2x^2

    If you know Calculus ....
    d(area)/dx = 517 - 4x
    = 0 for a max of area
    x = 517/4 =129.25
    y = 86.167 m

    (maximum area = 3xy = 33411.125

    Check by taking a value of x slightly smaller and slightly larger and finding their areas

    e.g
    x =129 , then y = 86.3333
    area = 3xy = 33411 , just a bit smaller

    x = 130, then y = 85.6666..
    area = 3xy = 33410 , again a bit smaller

    my answer is plausible.

  • Math -

    What is the answer for 104.19 + 4.9

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