An apparatus consists of a 2 L flask containing
nitrogen gas at 25�C and 819 kPa, joined by
a valve to a 12 L flask containing argon gas
at 25�C and 51 kPa. The valve is opened and
the gases mix. What is the partial pressure of
nitrogen after mixing?
Answer in units of kPa
What is the partial pressure of argon after
mixing?
Answer in units of kPa
What is the total pressure of the gas mixture?
Answer in units of kPa
for the first one i did 2 divided by 14 times 819 and got 116.99 but i don't know how to do the other two problems
PN2 is right.
Why wouldn't you do pAr the way way.
51 x (12/14) = ?
Total P = pN2 + pAr
llo
To answer these questions, we need to use the ideal gas law, which states:
PV = nRT
Where:
P = pressure
V = volume
n = number of moles
R = ideal gas constant
T = temperature
First, let's find the number of moles of nitrogen and argon in each flask.
Using the equation PV = nRT, we can rearrange it to solve for n:
n = PV / RT
For the 2 L flask containing nitrogen:
P_nitrogen = 819 kPa
V_nitrogen = 2 L
T_nitrogen = 25°C = 298 K (convert from Celsius to Kelvin by adding 273)
R = 8.314 J/(K mol)
n_nitrogen = (819 kPa * 2 L) / (8.314 J/(K mol) * 298 K)
n_nitrogen = 0.0662 mol
Similarly, for the 12 L flask containing argon:
P_argon = 51 kPa
V_argon = 12 L
T_argon = 25°C = 298 K
R = 8.314 J/(K mol)
n_argon = (51 kPa * 12 L) / (8.314 J/(K mol) * 298 K)
n_argon = 0.2342 mol
Now, let's calculate the total moles of gas after mixing by adding the moles of nitrogen and argon:
Total moles = n_nitrogen + n_argon
Total moles = 0.0662 mol + 0.2342 mol
Total moles = 0.3004 mol
Finally, to calculate the partial pressure of nitrogen and argon after mixing, we use the formula:
Partial pressure = (moles of the gas / total moles) * total pressure
For nitrogen:
Partial pressure of nitrogen = (n_nitrogen / total moles) * total pressure
Partial pressure of nitrogen = (0.0662 mol / 0.3004 mol) * total pressure
Similarly, for argon:
Partial pressure of argon = (n_argon / total moles) * total pressure
Partial pressure of argon = (0.2342 mol / 0.3004 mol) * total pressure
To obtain the total pressure of the gas mixture, you need to add the partial pressures of nitrogen and argon.
Total pressure = partial pressure of nitrogen + partial pressure of argon
With these calculations, you should be able to answer all the questions.