math
posted by pradyumna .
in a rectangular field adjacent sides differ by 17 cm.its diagonal length is 25 cm.find the cost of fencing the field at rs 5 per metre

s^2 + (s+17)^2 = 25^2
s = 8
The field is 8x17 cm
What a tiny field!
cost is thus 2(8+17)cm * rs5/m * 1m/100cm = rs 2.5
How odd: since a=8,b=17
a+b = √(a^2+b^2) 
My bad. I was thinking of an 81517 triangle.
s=7
2(7+25)*5/100 = rs 3.20 
rats! still bad arithmetic
7+17=24, not 25
you fix it