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in a rectangular field adjacent sides differ by 17 cm.its diagonal length is 25 cm.find the cost of fencing the field at rs 5 per metre

  • math -

    s^2 + (s+17)^2 = 25^2
    s = 8
    The field is 8x17 cm
    What a tiny field!

    cost is thus 2(8+17)cm * rs5/m * 1m/100cm = rs 2.5

    How odd: since a=8,b=17
    a+b = √(a^2+b^2)

  • math - oops -

    My bad. I was thinking of an 8-15-17 triangle.

    s=7

    2(7+25)*5/100 = rs 3.20

  • math -

    rats! still bad arithmetic
    7+17=24, not 25
    you fix it

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