find the perimeter of the norman window if a= 11 ft and b= 14 ft
p = 14+11+14+11pi/2 = 39 + 11pi/2
To find the perimeter of the Norman window, you need to add up the lengths of all its sides.
A Norman window is a rectangular shape with a semicircle on top. So, the perimeter consists of three parts: the bottom side, the two vertical sides, and the semicircular arch on top.
First, let's find the perimeter of the bottom side and the two vertical sides:
The length of the bottom side is given as a = 11 ft.
The length of the two vertical sides is given as b = 14 ft.
To calculate the perimeter of the bottom side and the two vertical sides, we need to add all three lengths together:
Perimeter = a + b + b = 11 ft + 14 ft + 14 ft = 39 ft.
The last part is to find the circumference of the semicircular arch on top:
The semicircle's diameter is given as a = 11 ft.
The formula for the circumference of a circle is C = πd, where C is the circumference and d is the diameter.
Since we have the diameter, we can calculate the circumference by substituting the values into the formula:
C = π * 11 ft.
To find the approximate value, use the approximation π ≈ 3.14:
C ≈ 3.14 * 11 ft ≈ 34.54 ft.
Now, to find the total perimeter of the Norman window, we need to add the circumference of the semicircle to the perimeter of the bottom side and the two vertical sides:
Total Perimeter = Perimeter of bottom and vertical sides + Circumference of the semicircular arch
Total Perimeter = 39 ft + 34.54 ft = 73.54 ft.
Therefore, the perimeter of the Norman window is approximately 73.54 feet.