# chemistry

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If 4.32 g of Cu combines with 1.09 g of S to form 5.41 g of chalcochite, what is the empirical formula of chalcochite?

• chemistry -

4.32g Cu = .068 moles Cu
1.09g S = .034 moles S

.068 : 034 = 2:1, so it looks like C2S

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