If 4.32 g of Cu combines with 1.09 g of S to form 5.41 g of chalcochite, what is the empirical formula of chalcochite?
4.32g Cu = .068 moles Cu
1.09g S = .034 moles S
.068 : 034 = 2:1, so it looks like C2S
1.09g S = .034 moles S
.068 : 034 = 2:1, so it looks like C2S