What structure do you get when you mix benzoic acid with H3O+? Where benzoic acid is a benzene ring with COOH attached to one of the hydrogens in the ring?

Please help!

These reactions usually occur with more then H3O+; is it just benzoic acid and H3O+, or is their something else, such as LiAlH4? If it is then you should get phenol, if not then I am not sure.

With straight H3O^+ there is no reaction with benzoic acid. It shifts the equilibrium of the benzoic acid to the left but that's all.

C6H5COOH + H2O ==> H3O^+ + C6H5COO^-

Okay thank you! I believe I figured it out as the H3O+ was just apart of a previous reaction that had occurred. They were put separately so it threw me off at first

To determine the structure obtained when benzoic acid (C6H5COOH) is mixed with H3O+ (hydronium ion), we need to understand the reaction involved. When benzoic acid reacts with H3O+, it undergoes an acid-base reaction known as protonation.

In this reaction, the hydronium ion (H3O+) acts as a proton donor (acid), while the benzoic acid acts as a proton acceptor (base). The H3O+ donates a proton (H+) to the oxygen atom of the COOH group in benzoic acid.

The reaction can be represented as follows:

C6H5COOH + H3O+ → C6H5COOH2+ + H2O

The result of this reaction is the formation of a new species, where the oxygen atom in benzoic acid is now protonated. The structure obtained is called a benzoic acid dihydrate ion (C6H5COOH2+). The H3O+ ion becomes H2O after donating its proton.

It's important to note that in the resulting benzoic acid dihydrate ion, the positive charge is delocalized over the oxygen atom and the adjacent carbon atom, due to resonance within the benzene ring.

So, when benzoic acid is mixed with H3O+, the structure obtained is the benzoic acid dihydrate ion (C6H5COOH2+).