mathsurgently needed[Differential equations]
posted by Anonymous .
solve
dy/dx = 2xy + (y^2/x^2)

mathsurgently needed[Differential equations] 
Steve
Looks like a Riccati equation. Standard methods, such as those at
http://www.sosmath.com/diffeq/first/riccati/riccati.html
will lead to the solution
y = xe^(x^2) / (cx + e^(x^2)  πix erf(ix))
where erf(x) is the error function. 
mathsurgently needed[Differential equations] 
Dr. Fairman
Use wolframalpha dot com  it will solve yr equation and show all steps.
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