maths-urgently needed[Differential equations]
posted by Anonymous .
dy/dx = 2xy + (y^2/x^2)
Looks like a Riccati equation. Standard methods, such as those at
will lead to the solution
y = xe^(x^2) / (cx + e^(x^2) - πix erf(ix))
where erf(x) is the error function.
Use wolframalpha dot com - it will solve yr equation and show all steps.