Equation:
3CaCl2 (aq) + 2 Na3PO4 (aq) → Ca3(PO4)2 (s) + 6 NaCl (aq)
How many grams of Ca3(PO4)2 are formed when 450.0 g NaCl are formed in the reaction?
please show steps, please
To find the mass of Ca3(PO4)2 formed, we need to calculate the moles of NaCl first and then use the stoichiometry of the balanced equation to convert the moles of NaCl to moles of Ca3(PO4)2, and finally, convert moles to grams. Here are the steps:
1. Determine the molar mass of NaCl:
Na: 22.99 g/mol
Cl: 35.45 g/mol
Molar mass of NaCl = 22.99 + 35.45 = 58.44 g/mol
2. Calculate the moles of NaCl:
Moles = Mass / Molar mass
Moles of NaCl = 450.0 g / 58.44 g/mol ≈ 7.706 mol
3. Use the stoichiometry of the balanced equation to find the moles of Ca3(PO4)2 formed:
From the balanced equation, we can see that the molar ratio between NaCl and Ca3(PO4)2 is 6:1.
Moles of Ca3(PO4)2 = Moles of NaCl / 6 ≈ 7.706 mol / 6 = 1.284 mol
4. Calculate the molar mass of Ca3(PO4)2:
Ca: 40.08 g/mol
P: 30.97 g/mol
O: 16.00 g/mol
Molar mass of Ca3(PO4)2 = (3 * 40.08) + (2 * 30.97) + (8 * 16.00) = 310.18 g/mol
5. Convert moles of Ca3(PO4)2 to grams:
Mass = Moles * Molar mass
Mass of Ca3(PO4)2 = 1.284 mol * 310.18 g/mol ≈ 398.13 g
Therefore, approximately 398.13 grams of Ca3(PO4)2 are formed when 450.0 g of NaCl are produced in the reaction.
To find the number of grams of Ca3(PO4)2 formed when 450.0 g NaCl is produced, we'll use the stoichiometry of the balanced equation.
Step 1: Calculate the molar mass of NaCl (sodium chloride).
The molar mass of NaCl is 22.99 g/mol (sodium) + 35.45 g/mol (chlorine) = 58.44 g/mol.
Step 2: Determine the number of moles of NaCl produced.
We'll use the formula: Moles = Mass / Molar Mass.
Moles (NaCl) = 450.0 g NaCl / 58.44 g/mol = 7.70 mol NaCl.
Step 3: Use the stoichiometry of the balanced equation to find the molar ratio between NaCl and Ca3(PO4)2.
From the balanced equation, we see that the molar ratio of NaCl to Ca3(PO4)2 is 6:1. This means for every 6 moles of NaCl, 1 mole of Ca3(PO4)2 is formed.
Step 4: Calculate the number of moles of Ca3(PO4)2 formed.
Since the molar ratio between NaCl and Ca3(PO4)2 is 6:1, the moles of Ca3(PO4)2 formed will be:
Moles (Ca3(PO4)2) = (7.70 mol NaCl) / 6 = 1.28 mol Ca3(PO4)2.
Step 5: Calculate the molar mass of Ca3(PO4)2 (calcium phosphate).
The molar mass of Ca3(PO4)2 is calculated by adding the atomic masses of all the elements:
3(40.08 g/mol) + 2(31.00 g/mol) + 8(16.00 g/mol) + 2(16.00 g/mol) = 310.18 g/mol.
Step 6: Calculate the mass of Ca3(PO4)2 formed.
The mass of Ca3(PO4)2 formed is calculated using the formula: Mass = Moles * Molar Mass.
Mass (Ca3(PO4)2) = 1.28 mol * 310.18 g/mol = 397.46 g Ca3(PO4)2.
Therefore, approximately 397.46 grams of Ca3(PO4)2 are formed when 450.0 g of NaCl is produced in the reaction.
mols NaCl = grams/molar mass
Using the coefficients in the balanced equation, convert mols NaCl to mols Ca3(PO4)2.
Now convert mols Ca3(PO4)3 to grams. g = mols x molar mass.
Equation:
3CaCl2 (aq) + 2 Na3PO4 (aq) → Ca3(PO4)2 (s) + 6 NaCl (aq)