Hg + I2 -> HgI2
Whats the mass of HgI2 if you have 0.7236g mercury and 0.3264g iodine?
A limiting reagent problem. I know because amounts are given for BOTH reactants.
mols Hg = grams/molar mass = approximately 0.0035 but you need to it more accurately.
mols I2 = about 0.0013
Using the coefficients in the balanced equation, convert mols Hg to mols of the product.
Do the same for mols I2.
It is likely that the two values for mols HgI2 will not be the same which means one of the numbers is wrong for mols HgI2. The correct value in limiting reagent problems is ALWAYS the smaller value and the reagent producing that value is the limiting reagent.
Using the smaller value, convert mols to grams. g = mols x molar mass.