John has 3 unique coins such that the probability of obtaining a head when the coin is flipped is 110, 210 and 310, respectively. If he flips each of the 3 coins once, the probability that at least 1 heads appears is p. What is the value of 1000p?
the probability of any event is a number p such that
0 ≤ p ≤ 1
Your data makes no sense.
she meant
1/10 and 2/10 3/10
answer ?
To find the probability that at least one head appears when flipping each of the 3 coins once, we can use the complement rule. The complement of "at least one head appears" is "no head appears."
The probability of no head appearing when flipping a coin is given by the equation:
P(no head) = (1 - probability of obtaining a head)
For the first coin, the probability of obtaining a head is 110/1000, which means the probability of no head is 1 - 110/1000 = 890/1000.
For the second coin, the probability of obtaining a head is 210/1000, which means the probability of no head is 1 - 210/1000 = 790/1000.
For the third coin, the probability of obtaining a head is 310/1000, which means the probability of no head is 1 - 310/1000 = 690/1000.
Since the flips of each coin are independent events, we can multiply the probabilities:
P(no head for all 3 coins) = (890/1000) * (790/1000) * (690/1000)
Now, using the complement rule, we find the probability that at least one head appears:
P(at least one head) = 1 - P(no head for all 3 coins)
To calculate this probability, we can do the following:
1. Calculate P(no head for all 3 coins):
P(no head for all 3 coins) = (890/1000) * (790/1000) * (690/1000)
2. Calculate P(at least one head):
P(at least one head) = 1 - P(no head for all 3 coins)
3. Multiply P(at least one head) by 1000 to get 1000p:
1000p = 1000 * P(at least one head)
By substituting the values into the equations, we can find the value of 1000p.