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physics

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A rotten cranberry will lose at least 90% of its total energy during a bounce. If the cranberries are dropped from a height of 10 cm, what is the minimum height in cm of the wall so that no rotten cranberries could ever bounce over it?

  • physics -

    ANSWER IS 1CM. SOLUTION TOTAL MECHANICAL ENERGY= TO K.E+P.E =0.5MASS VSQUARE+MASS GH
    K.E TOP +P.E TOP= K.E BOTTOM +P.E BOTTOM
    0+0.5MVSQUARE=M(9.81)(0.1)
    V=1.400 MASS M/SEC
    90% LOSE OF ENERGY
    M.E=MASS(G)(H) @ THE TOP
    M.E=MASS (9.81)(0.1)
    M.E=MASS 0.981
    REDUCTION OF 90% DURING BOUNCE
    M.E= MASS 0.981-MASS 0.981(0.9)
    M.E= MASS 0.0981
    MASS 0.0981=MASS (9.81)(H)
    H=0.01M OR 1CM

    edsel salariosa

  • physics -

    ANSWER IS 1CM. SOLUTION TOTAL MECHANICAL ENERGY= TO K.E+P.E =0.5MASS VSQUARE+MASS GH
    K.E TOP +P.E TOP= K.E BOTTOM +P.E BOTTOM
    0+0.5MassVSQUARE=Mass(9.81)(0.1)+0
    V=1.400 MASS M/SEC
    90% LOSE OF ENERGY
    M.E=MASS(G)(H) @ THE TOP
    M.E=MASS (9.81)(0.1)
    M.E=MASS 0.981
    REDUCTION OF 90% DURING BOUNCE
    M.E= MASS 0.981-MASS 0.981(0.9)
    M.E= MASS 0.0981
    MASS 0.0981=MASS (9.81)(H)
    H=0.01M OR 1CM
    since the mass of a object doesn't given you can cancel both side of the equation and you can find the height



    edsel salariosa
    research and development engineer

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