the radius of a chlorine atom is 99 pm and its mass is 5.89 X 10^-23 grams what is the density
I am assuming that 99pm means pico meters, so 99pm = 99 x 10^-7 cm
D=mass(g)/volume(cm3)
Plug in the value for radius into the equation to solve for the volume which will have units of cm^3
v=4/3πr^3
Since density=mass(g)/volume(cm3),
Solve for density,
D= (5.89 X 10^-23 g/volume calculated in cm^3)
so to get volume, you do v=(1.33)*3.14*99e-7^3????
Yes.
But, I gave you the wrong units for 99pm in cm, it should be 99x10^-10. I apologize about that
To calculate the density of an atom, you'll need the mass and volume. The mass is given as 5.89 x 10^-23 grams, but you need to find the volume of a chlorine atom given its radius of 99 pm.
1. Convert the radius from picometers (pm) to centimeters (cm):
Since 1 pm is equal to 1 x 10^-10 cm, the radius of 99 pm is:
99 pm × (1 x 10^-10 cm/pm) = 9.9 x 10^-9 cm
2. Calculate the volume of the atom:
The volume of a sphere is given by the formula V = (4/3)πr^3, where π is pi, and r is the radius. Plugging in the radius, we have:
V = (4/3)π(9.9 x 10^-9 cm)^3
V ≈ (4/3)(3.14)(9.9 x 10^-9 cm)^3
V ≈ 4.08 x 10^-23 cm^3
3. Calculate the density:
The density of an atom is given by the formula density = mass / volume.
Plugging in the mass and volume values we found, we have:
density = (5.89 x 10^-23 grams) / (4.08 x 10^-23 cm^3)
density ≈ 1.44 grams/cm^3
Therefore, the density of the chlorine atom is approximately 1.44 grams per cubic centimeter (g/cm^3).